Lab 12 | Physics homework help
2) f 2 . (16) Comparing Eqn. (15) and Eqn. (16), we then have: slope : m= μλ2 2 = F / f 2 . (17) Since there are two segments, we have:λ = λ2 = L . (18) Then, calculated value for quantity in Eqn. (17): μλ2
2 =μ L2 .(19)
F f 2 slope→μλ2 2 Measurement #2 We vary the the wavelength (# of segments)λn , while keeping the frequency fixed atf = 130Hz , and then plotFn vs.λn 2 . So we haveλn 2 along the x-axis andFn along the y-axis. We fit a straight line equation to the plot. Then the equation of this fitted straight line will be: Fn = mλn 2 + b . (20) We can rewrite Eqn. (13), as: Fn = (μ f 2)λn 2 . (21) From Eqn. (20), we then have: slope : m= μ f 2= Fn/ λn 2 . (22) Then, calculated value for quantity in Eqn. (22): μ f 2= μ(130)2 (23) Fn λn 2 slope→μ f 2 End of Theory Provided data for Exp 12 and instructions for data analysis and lab report